Question

Use the substitution method to solve the following system of equations
x + 2y – z = 2
3x + y – 2z = –15
3x + 4y – 3z = –2

Answer 1

solve the first equation for x.

x = 2-2y+z

then substitute x into the next equation and solve for y

3*(2-2y+z) +y - 3z = -15

then substitute that in to the third equation and solve for z

Answer 2

oops.. typo.

x = 2-2y+z

then substitute x into the next equation and solve for y

3*(2-2y+z) +y - 2z = -15

then substitute that (after you solve for y) in to the third equation (along with what you have for x) and solve for z

Answer 3

so what solution do i get