A car is initially moving with a velocity of 3 m/s. then it accelerates uniformly at the rate of 0.6 m/s^2 for 5 seconds. What is the distance traveled by the car in 5 seconds?
\[s = V_o*t + \frac{1}{2}*a*t^2 \]
ahhh I dont understand this stuff.
\[s = 3 \times 5 + \frac{1}{2}\times 5^2 \times .6\] \[s = 15 + \frac{1}{2}\times 25\times \frac{6}{10}\]
this will give me the distance?
I don't understand it either but I keep practicing, you must practice and keep trying; you will understand all this soon. Yes, It will
i am seriously behind. like my labs, I am like 6 weeks behind >.< due to not understanding! would you mind helping me with my quiz?
I will try my best! I am so behind too only 5 months left and I have to complete Mechanics, Thermodynamics, Optics, Electrostats and Modern Physics, Life hits you hard sometime
22.5
holy crap kidddo! :) you very sciencey...not a word, i know.. but WOW! I would really appreciate teh help :)
bharatindians! That was right!!! Thank you :))
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|dw:1320517096784:dw| so thevertical is position(x) and horizontal is time (sec) its asking if it represents uniform velocity, unirform accerleration, the objesct is at rest , or its accelerationg and decelerating..I have no idea?
HELP! PLEASE!?
accelerating according to me
thats what i thought, nbut idk what any of the uniform ones mean or what not :/
oh wait it must be uniform acceleration
:) imma just post the quiz stuff here kay?
the graph is position time I assumed it as velocity time silly me sorry it must be uniform acceleration yeah it's fine with me
What does the area under the velocity-time graph represent? (Points : 1) acceleration displacement speed velocity
displacement, pretty sure this time
i said volcity :/
oh my bad =P
An object is thrown with an initial velocity of 3 m/s. What is its acceleration at its maximum height? (Points : 2) zero 3 m/s2 9.8 m/s2 none of the above I saidzero :/
umm I think it's 9.8
Gravity Works all the time
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