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Mathematics 6 Online
OpenStudy (anonymous):

prove that \[\frac{a}{b}+\frac{c}{d} = \frac{ad + cb}{bd} ; b,d \neq 0\] prove that \[\frac{a}{b}+\frac{c}{d} = \frac{ad + cb}{bd} ; b,d \neq 0\] @Mathematics

OpenStudy (anonymous):

Come on mathemagician... you can do it!

OpenStudy (anonymous):

\[(a*b^{-1} + c*d^{-1})(bd)*(bd)^{-1}\]thats it

OpenStudy (anonymous):

you first distribute the (bd) and then you put everything under the (bd)^-1

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