Question

can some one explain how 25(4a^2-4ab+b^2) = 25(2a-b)(2a-b) when factoring completely?

Answer 1

to be specific, 25(2a-b)^2 is the lowest way to factor this. Because:
4a^2-4ab+b^2 factors to (2a-b)(2a-b) = (2a-b)^2
We then add in our constant multiplier and have
25(2a-b)^2

Answer 2

i understand that 25(2a-b)(2a-b) = 25(2a-b)^2 i just dont understand how you get from 4a^2-4ab+b^2 to (2a-b)^2

Answer 3

thats what i dont understand..

Answer 4

4a^2-4ab+b^2
2a(2a-b+b^2)
(2a-b)(2a-b)
does that help?

Answer 5

uhhhmm i dont think so :/ im having a hard time trying to grasp this.

Answer 6

http://www.wtamu.edu/academic/anns/mps/math/mathlab/col_algebra/col_alg_tut7_factor.htm

Answer 7

omg college algebra! im in the 10th grade! haha thanks though!