Question

how to solve x^3(y'-x)=y^2

Answer 1

whats that? y prime?

Answer 2

yes

Answer 3

is this DE

Answer 4

yes

Answer 5

ok did you arived yet in
dy/dx -(1/x^3)y^2 =x

Answer 6

yes

Answer 7

dy/dx -(1/x^3)y^2 =x
integral of dy=y=integral of [ x+(x^-3)(y^2)]dx try intgrating that

Answer 8

y=integral of [ x+(x^-3)(y^2)]dx
y=(x^4-y^2)/2x^2