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For how long must $700 be left on deposit at 6% compounded monthly to reach a total accumulation of $1750? (Note: I know how to find this with a calculator, I would like to see the mechanic of how LN would be used to solve this...thanks)
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your job is to solve \[700(1+\frac{.06}{12})^{12t}=1750\] for t
or \[700(1.005)^{12t}=1750\] divide by 700 get \[(1.005)^{12t}=2.5\] then using logs get \[12t=\frac{\ln(2.5)}{\ln(1.005)}\] or \[t=\frac{\ln(2.5)}{12\ln(1.005)}\]now you really need a calculator, because you cannot do this with arithmetic
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