Beverly can drive 600 miles in the same time as it takes susan to drive 500 miles. If beverly drives 10 mph faster than susan, then how fast does beverly drive? What would the algebraic equation setup for this problem be?

Question

Beverly can drive 600 miles in the same time as it takes susan to drive 500 miles. If beverly drives 10 mph faster than susan, then how fast does beverly drive?        What would the algebraic equation setup for this problem be?

radar · Answer

Let x = rate of Susan in mph,
then x+10 is the rate of Beverly.

d=rt distance equals rate times time.
t=d/r   
600/(x+10) =500/x   t=t

anonymous · Answer

Thank you very much it's all clear now.

radar · Answer

Solving by cross multiplying getting 600x=500x+5000
100x=5000
x=50 mph
x+10 =60 mph

radar · Answer

ur welcome,