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Mathematics 25 Online
OpenStudy (anonymous):

Find the surface area of the part of the sphere x^2+y^2+z^2=64 that lies above the cone z=sqrt(x^2+y^2) I converted it to polar form and got the double integral of 64/(sqrt(64-r^2) , however I am not sure if that is correct nor am I sure if my limits of integration are correct. Please help!

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