Question

graph the following parabola:
y=6(x+3)^2-2

Answer 1

For a parabola I was told all you need is three points: vertex and two other points.
So vertex is (-3,-2). I also have the points (-2,4) and (-4,4)

Answer 2

wait how did you find the other two points?

Answer 3

I chose an x-coordinate close to the vertex. So x=-2 and substituted it into the equation of the parabola. I know that the parabola is symmetrical vertically so x=-4 would give me the same value as x=-2.

Answer 4

so you just pick a random number and plug it into the equation?

Answer 5

Pick a number that would give you a small y-value. Like i know if i use -2. The (-2+3) part will be small

Answer 6

oh okay! thank you!!