Write the equation in slope intercept form of the line that is parallel to y=-3x+5 and contains (2,-3)?
i WILL GIVE ANYONE A MEDAL WHO HELPS ME WITH THIS QUESTION
First of all, if it is parallel to y = -3x + 5, then it has the same slope.
So, we have y = -3 x + b, and it goes through the point (2, -3) so we plug the x and y values into to the equation to find b.
-3 = -3 * 2 + b -3 = -6 + b ( add 6 to both sides) b = 3 so the equation is y = -3x + 3
thankyou, can you answer another question similar to the one you just answered?
sure
ok thanks!
Write the equation in slope intercept form for the line that contains (-4,-2) and is perpendicular to the line y=1/4x-7
If the line is perpendicular, the the slope is equal to the negative reciprocal of the line you have. y = 1/4 x - 7 In other words the slope for the line you are looking for is -4 y = -4 x + b The rest is the same, plug in the x and y values from your point and solve for b.
Think you can handle it from there?
is the Answer y= -4x-8 ?
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u wanna help me please? i have a test tommorrow?
it's y = -4 x + 14 Can you show me how you got b = -8, I might be able to figure out where you're mistake was
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