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0= -3x^2+2x-1 0= -3x^2+2x-1 @Mathematics
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3x^2 - 2x +1 = 0 now solve for x
Alright I'm trying to factor it out... I'm getting stuck though I set it up as (3x __) (x__)
x_1,_2=(2+/- sqrt(4-12))/12 = (1+/- isqrt2)/6
sorry first divide by 6 not by 12 than simplify by 2 you will get (1+/- isqrt2)/3
I don't think this is a problem that has a square root in it lol, it's just factoring
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so but how you wann to factoriz it ?
to get those factors you need first to solve it
well I need to un-factor it I say. so I want it to end up as an answer in two brackets __> ( ) so it's 3x^2-2x+1 so I've set it up so far as (3x ??) (x ??)
(3x-1-isqrt2)(3x-1+isqrt2) check it please
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