Question

Differentiate 2x^2-6x^2+y^3=26 with respect to t (x and y are functions of t)

Answer 1

take the derivative and put
\[x'=\frac{dx}{dt}\] or
\[y'=\frac{dy}{dt}\] after each one.

Answer 2

but first, so you really have
\[2x^2-6x^2=-4x^2\]as the first two terms?

Answer 3

4x(dx/dt)-12x(dx/dt)+3y^2(dy/dt)=0

Answer 4

so I solve for y? and then find the derivative?

Answer 5

\[4x * x \prime - 12y* y \prime + 3y2*y \prime?\]