Solve the logarithm In x = 2 Solve the logarithm In x = 2 @Mathematics
7.389
ln is the same as log base e
or e^2
0.6931
no, .6391 yields a negative answer
with base 10,it is,0.301
What you got was ln(2) which is not right
do you get what to do in these problems? they are very simple: raise e to the power of both sides e^(lnx)=e^2 x=e^2
x=e squared
The value of log2 depends on the base of the logarithm. log without a subscript usually measn base 10, but is sometimes used for base e. base 10: log2 = 0.3010299956 ≈ 0.30103 base e: log2 = 0.69314718
No, we need to solve for x in ln(x)=2
thn,it is e2
Thank you, can someone show the work? cause i dont understand how to exactly do this kind of lagarithm
no lg signe logarithm on base 10
Check tourist Test's post, he explained it
Test showed the work a bit up
check wikipedia
\[\ln x = 2 \]\[e^{\ln x}=e^2\]\[x=e^2\]
on wikipedia
if it were base 5 for example:\[\log_5x=2\]\[5^{\log_5x}=5^2\]\[x=5^2=25\]just watch the bases
Thank you everyone, and thank you soo much turingtest for the explanation :D
no prob :)
You are the best, and helped me really understand when you helped me with all my problems lol ^^
I try!
Hehe thank you again :)
Join our real-time social learning platform and learn together with your friends!