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Solve |2y - 2| = y. A. {2/3, 2} B. {2, 3} C. {2, 5} D. {1/3, 2} Solve |2y - 2| = y. A. {2/3, 2} B. {2, 3} C. {2, 5} D. {1/3, 2} @Mathematics
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2y-2=y and 2y-2=-y 2y=y+2 and 2y=2-y y=2 and y=2/3
so A
Okay thank you
do you understand how I got that?
No not really
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ok well this is how you do it abs(whatever)= something this means that (whatever)=soemthign and (whatever)=negative something so forexample abs(x)=3 means x=3 and x=-3 also if it said abs(x) + 2=3, this means you have to isolate the absolute to just itself so it would be abs(x)=1 [subtract the 2] Does that help?
Um yea actually it does.
Okay so do you think you can help me with the question i just posted
sure
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