derivative of 1/bx?
I know.... so easy, just bear with me @Calculus1
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OpenStudy (anonymous):
1/bx=bx^-1
y'= -1(bx)^-2 * (b+x)
OpenStudy (eyust707):
no not b+x
OpenStudy (anonymous):
I know that isn't right ^^^ ... why in the world am I messing up!
It's so simple too... Maybe I need to take a break. Been studying for 6 hours straight lol
OpenStudy (anonymous):
chain rule?
OpenStudy (eyust707):
yep
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OpenStudy (eyust707):
what the derivitive of bx?
OpenStudy (anonymous):
deriv of first times second + deriv of second times first
1x+1b
OpenStudy (eyust707):
chain rule says
"take the derivative of the outside then multiply it by the derivative of whats on the inside"
OpenStudy (eyust707):
that is the product rule you are using... typically b is assumed to be a constant