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Complete the square on the quadratic y=-2x^2+3x+6
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please show your work
I have gotten this far y=-2(x^2+3x)+6 Y=-2(x^2+? what at this point
y = -2(x^2+[3x/-2]-3)
When you factor out a number from each term, you divide that number by each term.
So is this as far as I go then i solve for th y intercept?
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I think you were doing it right. You just needed to understand how to find the middle term.
I just don't know what to do after I find that term. I seem to be having a mental block
You just have to find the complete square by adding (b/2)^2 and then reducing the terms to the form (x-a)^2
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