when lg y is plotted against lg x, you get a straight line passing through (4,12) and (6,17).

so basically the gradient of the straight line is 2.5

I need to express y in terms of x, giving my answer in the form y = ax^b.

I've done:

lg y = lg x^2.5 + 2. Can anyone help me finish it?? thanks :)

Question

when lg y is plotted against lg x, you get a straight line passing through (4,12) and (6,17).

so basically the gradient of the straight line is 2.5

I need to express y in terms of x, giving my answer in the form y = ax^b.

I've done:

lg y = lg x^2.5 + 2.      Can anyone help me finish it?? thanks :)

anonymous · Answer

how are you plotting lg y against lg x ?  you are tweaking the coordinate axis?

anonymous · Answer

Yes. we had learnt it during ad maths. Basically by changing the co-ordinate axis's, we can change the formula to make it a straight line graph.

anonymous · Answer

Okay .. what are the new coordinate axis now ? x= ln(x) and y = ln(y) ?

anonymous · Answer

in that case it don't makes much sense........

anonymous · Answer

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