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Mathematics 21 Online
OpenStudy (anonymous):

solve the system for xandy. 3x-y2=0 x^2-y^2=4

OpenStudy (anonymous):

so far i solved for y and got plus or minus an unreal solution for y...

OpenStudy (zarkon):

is the first equation supposed to be \[3x-y^2=0\]?

OpenStudy (anonymous):

on the y2 is it suppose to bee a exponent ??

OpenStudy (anonymous):

oh dang sorry its 3x-2y=0

OpenStudy (zarkon):

then there are no real solutions

OpenStudy (anonymous):

why?

OpenStudy (zarkon):

because they are both complex :)

OpenStudy (anonymous):

4 and -2 be the answer...???

OpenStudy (anonymous):

uhh ^^?

OpenStudy (anonymous):

so if i run into 1 complex solution, im guessing the system has no real solution?

OpenStudy (zarkon):

not always

OpenStudy (anonymous):

so i have to solve for both variables even if i run into a complex solution?

OpenStudy (zarkon):

it depends on the system

OpenStudy (zarkon):

this particular system...knowing one root is complex tells us that the other is also

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

is it because the way its showed on the graph? you know the other solution will be the reflection of the x axis

OpenStudy (zarkon):

if you solved the first equation for x or y and plugged it into the second you will get a second degree polynomial...if the roots are complex they will come in complex congugate pairs. then, the first equation ... being linear ...if one variable is complex then so is the other

OpenStudy (anonymous):

ok, that makes sense. so in the future im guessing i should just solve for both variables to make sure right?

OpenStudy (zarkon):

in general...that is a good idea

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