Question

how would you solve
6^(x^2+14x-38)=36^(6x-7) how would you solve
6^(x^2+14x-38)=36^(6x-7) @Mathematics

Answer 1

36 = 6^2 thus
36^(6x -7) = 6^(12x - 14)

Answer 2

james help meee

Answer 3

So now you know that
6^(x^2+14x-38)=6^(12x - 14)
and that can only be the case if

x^2 + 14x - 38 = 12x - 14.

Answer 4

Thank you so much!

Answer 5

$$6^{x^{2}+14x-38}=36^{6x-7}$$
$$6^{x^{2}+14x-38}=6^{2(6x-7)}$$
$$x^{2}+14x\ -38\ =\ 12x\ -14$$