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Write the given expression as a single logarithm. -3ln(x)+ln(4y)-ln(3z)
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ln(x^-3)(4y)(3z)= ln(12yz/x^3)
thats wrong for some reason
I believe you can write ln(x^-3*4y/3z)
\[-3\ln x+\ln4y-\ln3z\]\[\ln x^{-3}+\ln4y-\ln3z\]\[\ln 4yx^{-3}-\ln3z\]\[\ln \frac{4yx^{-3}}{3z}\]
Thanks guys! Since you guys are familiar with all this, can you help me with the other problems I posted?
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http://openstudy.com/users/mariomintchev#/users/mariomintchev/updates/4ebda4c8e4b021de86fd29b3
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