Question

A)Pick any five numbers. Compute the mean and standard deviation of this distribution. (List your five numbers.)

Numbers:
Mean:
Standard Deviation:




B) Multiply each number in your distribution by 3 and compute the mean and standard deviation of this new distribution.

Numbers Now:
Mean:
Standard Deviation:





C) Multiply each number in your original distribution by 9 and compute the mean and standard deviation of this new distribution.

Numbers Now:
Mean:
Standard Deviation:




D) What conclusion can you draw about the changes in the mean and the standard

Answer 1

\[1,1,1,1,1\]
mean=(1+1+1+1+1)/5

Answer 2

\[variance=\frac{(1-1)^2+(1-1)^2+(1-1)^2+(1-1)^2+(1-1)^2}{5}=0\]

Answer 3

\[standard deviation=\sqrt{variance}=\sqrt{0}=0\]

Answer 4

i leave the rest to you

Answer 5

ok..ty for the start

Answer 6

i don't know if your teacher wanted such an easy data

Answer 7

not sure its just confusing to me, im taking an online class

Answer 8

if we had
\[1,2,3,4,5\]
\[mean=\frac{1+2+3+4+5}{5}=\frac{15}{3}=5\]

Answer 9

I'm only doing part A but i'll show you how to do the rest.

A) Numbers: 2, 4, 6, 8, 10

Mean(average): 2+4+6+8+10= 30 add together then divide by number of numbers (5)

Mean=30/5 = 6

Standard Deviation = The square root of the average of the squared difference of the numbers from the mean. (mouthful?)

\[SD=\sqrt{\sum(number-average)^{2}/number of numbers)}\]

soo...

(2-6)^2=16
(4-6)^2=4
(6-6)^2=0
(8-6)^2=4
(10-6)^2=16

Add those numbers together... = 40

standard deviation = sqrt{40/5}

Answer 10

\[variance=\frac{(5-1)^2+(5-2)^2+(5-3)^2+(5-4)^2+(5-5)^2}{5}=\frac{16+9+4+1+0}{5}\]

Answer 11

\[varinace=\frac{30}{5}=6\]

Answer 12

\[standard deviation=\sqrt{variance}=\sqrt{6}\]

Answer 13

there now you have three examples

Answer 14

but i really like the data consisting of just 1's lol

Answer 15

ty sooo much this is a big help!

Answer 16

yea that's kind of funny

Answer 17

online courses are nice in way but lac in examples and help