If you were to use the substitution method to solve the following system, choose the new system of equations that would result if x was isolated in the second equation. 3x + y + 2z = 1 x + 2y – z = –8 3x – y – 3z = 18 –5y + 5z = 25 –7y = 42 –5x – 5z = –10 6x – z = 19 7x + 3z = –10 0x – 5z = 19 7y – z = 25 5y – 6z = 42 If you were to use the substitution method to solve the following system, choose the new system of equations that would result if x was isolated in the second equation. 3x + y + 2z = 1 x + 2y – z = –8 3x – y – 3z = 18 –5y + 5z = 25 –7y = 42 –5x – 5z = –10 6x – z = 19 7x + 3z = –10 0x – 5z = 19 7y – z = 25 5y – 6z = 42 @Mathematics
Step 1. Isolate x in second equation. x=-8+z-2y using algebra. Step 2. substitute this new value of x in first and third equation. First equation becomes 3(-8+z-2y)+y+2z=1 Third equation becomes 3(-8+z-2y)-y-3z=18 Step 3. Now simplify those equations. first one first:-24+3z-6y+y+2z=1 -5y+5z=25 third one next -24+3z-6y-y-3z=18 -7y=42 There you have it: -5y+5z=25 and -7y=42 The first two.
radar is correct.
Hello robtobey, how are things in CA?
Raining today. Otherwise everything is normal.
It has turned of windy and chilly, but lots of sunshine.
Where are you located again?
the Ozarks of MO
What is the highest elevation in your immediate area?
Tom Sauk Mt. however only 1772 ft. Doesn't compare to the sierrias or cascades etc.
Just checked out Truckee, CA at 5829 ft and it is snowing there today.
Is that up near Lake Tahoe?
It is on interstate 80 on the way to Reno, NV
going to pop some popcorn and watch some TV with my wife. CUL
Nice talking to you.
checking out you link. Good to hear from you.
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