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Find the line which is perpendicular to the graph of fx=x/(x+2) at x=2
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find derivative, find slope
you can first find y by plugging in x
y=2/4
now you have x,y need slope using derivative and then you are set to go
y-y1=m(x-x1)
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f'(x)=((x+2)(1)+(x)(1))/(x+2)^2
?
umm i use product rule give me a sec lol
f'(x) = 2/(2+x)^2 slope: 2/(2+x)^2 slope 2/(2+2)^2 slope = 1/8 perpendicular slope: -8 f(2) = 2/4 = 1/2 y = -8x +b 1/2 = -8 (2) +b b = 9/2 y = -8x + 9/2
oops i mean - not +
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i got -8/3 as my slope and my y=-8/3x+(35/6) is that even close?
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