Question

4sqrt{x} times 5sqrt{7x} 4sqrt{x} times 5sqrt{7x} @Mathematics

Answer 1

\[\sqrt[4]x \times \sqrt[5]7x\]

Answer 2

\[\sqrt[4]{x}*\sqrt[5]{7x}=x^{1/4}(7x)^{1/5}=x^{1/4}(7^{1/5})x^{1/5}=7^{1/5}x^{1/4+1/5}=7^{1/5}x^{9/20}\]that's 7^(1/5)x^(9/20) for the answer
(a bit difficult to read the 9)

Answer 3

oh, is the x under the radical or not?

Answer 4

if is is under the radical the answer is\[7^{1/5}x^{9/20}=\sqrt[5]7*\sqrt[20]{x^9}\]

Answer 5

yes it is

Answer 6

then the answer is above

Answer 7

do you follow?

Answer 8

yes thhanks!