Mathematics
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OpenStudy (anonymous):
Step-by-step how do i factor
y²+14s+49
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OpenStudy (anonymous):
is it s in middle term
OpenStudy (anonymous):
THX mark o. :)
OpenStudy (zarkon):
@mark o. what happened to the y and s
myininaya (myininaya):
they became x
x=y=s right mark-0
lol
OpenStudy (anonymous):
yeah same question i too have to ask
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OpenStudy (anonymous):
i too posted (y+7)^2 but after seeing s i deleted it
OpenStudy (anonymous):
right myininaya ....thnx.....lol
OpenStudy (anonymous):
step by step:
OpenStudy (anonymous):
y\[y^2+14s+49 find the common factor\]
OpenStudy (anonymous):
wtf no such equation can be factorised
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OpenStudy (anonymous):
but what common factor u will find fahminator
OpenStudy (anonymous):
it has to be 14y not 14s..... this cannot be factorised
OpenStudy (anonymous):
no common factor
OpenStudy (anonymous):
IM confused now :(
myininaya (myininaya):
do you realize you have s and y in your expression, joyce?
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OpenStudy (anonymous):
therefore we had do multiply the first coefficient by the 3rd coefficient
and find if i can use the factors of 49 to add to make 14
OpenStudy (anonymous):
yeah we know u r confused so after posting such question u thanked mark. o lol
OpenStudy (anonymous):
yeah you can’t do it if theres 14s... it has to be 14y OR s^2 in the beginning
myininaya (myininaya):
\[y^2+14y+49 \text{ can be factored}\]
\[s^2+14s+49 \text{ can be factored}\]
\[y^2+14s+49 \text{ cannot be factored}\]
OpenStudy (anonymous):
this equation was falsely written. this cannot be factorised any further
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OpenStudy (anonymous):
tis is what i mean ..lol,,it should be y not s
y^²+14y+49
=(y+7)(y+7)
=(y+7)^2
OpenStudy (anonymous):
oh nvm then because its completely false using a new variable in the equation...
OpenStudy (anonymous):
i put down exactly wut the Q was
OpenStudy (anonymous):
lol then its impossible
myininaya (myininaya):
ok then it isn't factorable
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OpenStudy (anonymous):
sometimes it cannot be factorable
OpenStudy (anonymous):
ANY FURTHER than what they have given you.
OpenStudy (anonymous):
ok thx
OpenStudy (anonymous):
just write down : impossible
OpenStudy (anonymous):
kk thx
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OpenStudy (anonymous):
what about this problem
x²+2x-15
myininaya (myininaya):
-15=5(-3)
and 2=5+(-3)
myininaya (myininaya):
\[(x+5)(x-3)\]
OpenStudy (anonymous):
kk thx