Question

Multiply
(2x^2 + 3x – 6)(x – 1) Multiply
(2x^2 + 3x – 6)(x – 1) @Mathematics

Answer 1

2x^3 + x^2 - 9x + 6

Answer 2

2x^3+3x^2-6x-2x^2-3x+6
= 2x^3+x^2-9x+6

Answer 3

oh my god thank you!

Answer 4

dammit...

Answer 5

they beat me to it

Answer 6

now can either of you show me step by step how to do that? i hate having to go on here to pretty much cheat.
I'd love to be able to understand it

Answer 7

here.

Answer 8

I'll give you a medal anyways :)

Answer 9

using the law of distribution, you must spread out the (x) and the (-1) to each one of the terms in the first bracket.

Answer 10

so,

Answer 11

\[(2x^2+3x-6)x+(2x^2+3x-6)(-1)\]

Answer 12

2x^2 times x + 3x times x - 6 times x

Answer 13

exactly what myininaya said.

Answer 14

\[2x^3+3x^2-6x+(-2x^2-3x+6)\]

Answer 15

Thank you guys so much!

Answer 16

\[2x^3+3x^2-2x^2-6x-3x+6\]

Answer 17

\[2x^3+(3-2)x^2+(-6-3)x+6\]

Answer 18

\[2x^3+1x^2+(-9)x+6\]
\[2x^3+x^2-9x+6\]