Find the difference. (6/x-2)-(12/x^2-4)
my answer was 6(x-4)/(x+2)(x-2). i think its wrong, can somebody check it?
6/(x - 2) - (12/X^2-4) common denominator is (x-2)(x+2) 6(x+2)/(x-2)(x+2) - 12/(x-2)(x+2) = 6x+12-12?(x-2)(x+2) = 6x/(x-2)(x+2)
i thought you had to distribute x-2. so doesnt the first part become 6x-12/x+2 x-2??
oh damn i made a mistake writing it. lol
the first part is really 6/x+4
No. The first fraction is 6/(x-2) so to write it with the common denominator the numerator and denominator both must be multiplied by (x+2) and 6(x+2) is 6x+12
(6/x+2)-(12/x^2-4) thats the proper equation :P
So now the top is 6(x-2) -12 or 6x-24
thats how i got 6(x-4)/(x+2)(x-2)
So your original answer is correct. You have factored the 6x-24
i just felt something was wrong. usually something ends up cancelling itself out :\ ill plug it in and see
yay its right :D
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