complete the square both numbers x^(2)+(3)/(4)x+_?_=(x+_?_)^(2)
i already did this
it wasnt right it said
i tried it
\[x^2+\frac{3}{4}x+(\frac{3}{4 \cdot 2})^2=(x+\frac{3}{4 \cdot 2})^2\]
you have to simplify i didn't do that for you
For crying out loud. I did it for him too.
\[(\frac{3}{4 \cdot 2})^2=(\frac{3}{8})^2=\frac{3^2}{8^2}=\frac{9}{64}\]
thats it simplified aw man no wonder i dont think thats all though
\[x^2+\frac{3}{4}x+(\frac{3}{4 \cdot 2})^2=(x+\frac{3}{4 \cdot 2})^2 \] this is all \[x^2+\frac{3}{4}x+\frac{9}{64}=(x+\frac{3}{8})^2\]
what do you use to write fractions and equations the way you do Myininaya?
thnk you so very much :)
do you see the equation thingy below the box you are typing in i use that sometimes frac{ a}{b} will give \[\frac{a}{b}\]
magic. she uses magic
ty
if you want to see the code, right click over the expression and choose "show source"
very cool
\[\color{#FF0099}{\overrightarrow{\text{myininaya}}}\]
that is a better color
i think you can use all web colors
you can pick your own. it is nice. now i have a question. will we ever reach level 101?
that is a question for shadowy
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