I need some help with an Algebra Question. Please help me. I need some help with an Algebra Question. Please help me. @Mathematics
Ax+By=C
Hi Chris I am still having strouble...
y = -1x/2 + 1 y -1 = -1x/2 2y -2 = -x 2y+x -2 = 0 8y + 4x -8 = 0
this looks weird m=-1/2 and b=1 is that what we are looking at y=mx+b y=-1/2 *x+1 1/2 *x+y=1 x+2y=2
yeah, I got what myininaya got
Alright So the equation you use is y-y1=m(x-x1)
and we got what moneybird got just add 8 on both sides and divide by 4 on both sides
i used y=mx+b as i stated above
no, the standard form is the Ax+By=c so the answer is x+2y=2
Thanks.
oh.. and yeah, you start with y=mx+b just like myinimaya said.
Haha, Ok Input in standard form the equation of the given line.The line with m = -3/8 and passing through (5, -4)
y=mx+b
no I think this is y-y1=m(x-x1)
yes, start with y=mx+b, plug in m, x, and y and solve for b.
-4=(-3/8)(5)+b
y-y1=m(x-x1) is the point-slope form. it's just another way to write the linear equation
\[y=mx+b \] m is -3/8 \[y=\frac{-3}{8}x+b\] we know a point on the line (5,-4) => x=5, y=-4 plug that in to figure out what b is \[-4=\frac{-3}{8} (5)+b \] \[-4+\frac{3}{8} \cdot 5=b\] \[-4+\frac{15}{8}=b \] \[\frac{-32+15}{8}=b\] \[b=\frac{-17}{8}\] so the equation is \[y=\frac{-3}{8}x+\frac{-17}{8}\]
-4=-15/8+b
-3x-17=y
In standard form??
3x+8y=-17
Oh yea sorry..
Input in standard form the equation of the given line.The line that passes through (-3, 5) and (-2, -6) Here I first find the slope of the equation. Then, do I still use the y=mx+b or do I use the other one?
-33x-5y=?
I would find the slope, just like you say, then use one set of your coordinates in y=mx+b to find your b, then convert the y=mx+b form to standard form.
So |dw:1321215104634:dw|
Join our real-time social learning platform and learn together with your friends!