Question

Square root of 4z + 1 equals 3 plus the square root of 4z - 2. How to do?

Answer 1

\[\sqrt{4z+1} = 3 + \sqrt{4z-2}\]

Answer 2

No solutions.
You square both sides to get rid of the square root on the 4z+1. Simplify.
You get 4z+1 = 9+6*sqroot(4x+2) + 4z -2
Subtract 4z from both sides.
1 = 9 + 6* sqroot (4z+2) - 2
1 = 7 + 6* sqroot (4z+2)
-1 = sqroot (4z+2)