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what is the outside function in y=[(ln(3z))^2] ? for chain rule
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squaring
^2 then ln(3z)
the squaring funcion \[S(x)=x^2\] because that is the last thing you would do if you were evaluating this for a specific value of x
so the inside would be ln(3z)?
1) multiply by 3 2) take the log 3) square
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no. 3z
so this is a composition of three functions in that order
sorry i meant then ln then 3z
so how would you write this exactly?
y=[ln(3z)]^2 dy = 2ln(3z)(1/3z)(3)
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still confused
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