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Write the product as a sum. 11sin(x/2)cos(x/4)
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forget the 11 for moment and you use \[\sin(\alpha)\cos(\beta)=\frac{1}{2}(\sin(\alpha +\beta)+\sin(\alpha -\beta))\]
in this case \[\alpha =\frac{x}{2},\beta=\frac{x}{4}\] so you can write this as \[\frac{11}{2}(\sin(\frac{3x}{4})+\sin(\frac{x}{4}))\]
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