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Mathematics 21 Online
OpenStudy (anonymous):

3^x^3=9^x

OpenStudy (anonymous):

can we simple bring the 3 down, and then you will have 9^x on the left hand side

OpenStudy (anonymous):

or am i confusing my logs and exp

OpenStudy (anonymous):

rules

OpenStudy (anonymous):

i think i have to make the bases te same first?

OpenStudy (anonymous):

the base is 9 correct

OpenStudy (zarkon):

\[9^x=(3^2)^x=3^{2x}\]

OpenStudy (zarkon):

solve\[x^3=2x\]

OpenStudy (anonymous):

right there you go, thats what i meant

OpenStudy (anonymous):

so it would be 3x=2 and then i figure it out from there?

OpenStudy (zarkon):

no

OpenStudy (zarkon):

\[x^3=2x\] \[x^3-2x=0\] \[x(x^2-2)=0\]

OpenStudy (anonymous):

3x^3 = 9x x^3=3x x^3-3x=0 x(x^2-3)= 0 x= 0 or x = +- root(3)

OpenStudy (anonymous):

oop s that was wrong srry

OpenStudy (zarkon):

the answer is \[x=0,\pm\sqrt{2}\]

OpenStudy (anonymous):

i agree with zark ...

OpenStudy (anonymous):

i miss read the question

OpenStudy (zarkon):

it took more keystrokes to do the dots than it would have to type 'on' ;)

OpenStudy (anonymous):

zarkon why is there an x connected to the 2?

OpenStudy (zarkon):

\[9^x=(3^2)^x=3^{2x}\]

myininaya (myininaya):

\[3^{x^3}=9^x\] \[3^{x^3}=(3^2)^x\] \[3^{x^3}=3^{2x} =>x^3=2x \]

myininaya (myininaya):

zarkon you look more human now

OpenStudy (zarkon):

plastic surgery...does wonders.

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