Mathematics
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OpenStudy (anonymous):
3^x^3=9^x
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OpenStudy (anonymous):
can we simple bring the 3 down, and then you will have 9^x on the left hand side
OpenStudy (anonymous):
or am i confusing my logs and exp
OpenStudy (anonymous):
rules
OpenStudy (anonymous):
i think i have to make the bases te same first?
OpenStudy (anonymous):
the base is 9 correct
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OpenStudy (zarkon):
\[9^x=(3^2)^x=3^{2x}\]
OpenStudy (zarkon):
solve\[x^3=2x\]
OpenStudy (anonymous):
right there you go, thats what i meant
OpenStudy (anonymous):
so it would be 3x=2 and then i figure it out from there?
OpenStudy (zarkon):
no
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OpenStudy (zarkon):
\[x^3=2x\]
\[x^3-2x=0\]
\[x(x^2-2)=0\]
OpenStudy (anonymous):
3x^3 = 9x
x^3=3x
x^3-3x=0
x(x^2-3)= 0
x= 0 or x = +- root(3)
OpenStudy (anonymous):
oop s that was wrong srry
OpenStudy (zarkon):
the answer is \[x=0,\pm\sqrt{2}\]
OpenStudy (anonymous):
i agree with zark ...
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OpenStudy (anonymous):
i miss read the question
OpenStudy (zarkon):
it took more keystrokes to do the dots than it would have to type 'on' ;)
OpenStudy (anonymous):
zarkon why is there an x connected to the 2?
OpenStudy (zarkon):
\[9^x=(3^2)^x=3^{2x}\]
myininaya (myininaya):
\[3^{x^3}=9^x\]
\[3^{x^3}=(3^2)^x\]
\[3^{x^3}=3^{2x} =>x^3=2x \]
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myininaya (myininaya):
zarkon
you look more human now
OpenStudy (zarkon):
plastic surgery...does wonders.