Question

How do I find the maximum value of: y = -3x^2 - 9x + 2 How do I find the maximum value of: y = -3x^2 - 9x + 2 @Algebra

Answer 1

using calculus ... find the derivative and set it = 0
not using calculus fund the vertex

Answer 2

Its for an Intermediate Algebra course haha

Answer 3

f'(x)= -6x -9

Answer 4

ok determine the vertex

y=-3(x^2+3x) +2
y=-3(x^2+3x +9/4-9/4) +2
y=-3(x +3/2)^2 +27/4+2
y=-3(x+3/2) +35/4

so max is 35/4 ... but check my arithmetic

Answer 5

max vale is the y value for the vertex vertex is at (-3/2,35/4)

Answer 6

So basically yuou just completed the square?

Answer 7

yes ... it was completed ... poor old thing ...

Answer 8

Thanks :)