Question

e^(2x)-15e^x+56=0 e^(2x)-15e^x+56=0 @Mathematics

Answer 1

solve
\[x^2-15x+56=0\] first and then replace x by e^x

Answer 2

or just factor as
\[(e^x-7)(e^x-8)=0\]
\[e^x=7, e^x=8\]
\[x=\ln(7), x=\ln(8)\]