http://www.artofproblemsolving.com/Wiki/index.php/2009_AMC_8_Problems Can anyone explain how to solve question 25 to me? http://www.artofproblemsolving.com/Wiki/index.php/2009_AMC_8_Problems Can anyone explain how to solve question 25 to me? @Mathematics
oh man, these look really tough
I just need 25.
Is AMC 8 tomorrow? Because AMC 8 is tomorrow for my school
Yep...last minute study panic XD I want to get 25.
Good luck!
This question is actually not very hard
First find height D
which is 1- 1/2 - 1/3 - 1/17
I got an answer of 6...but I want to check this.
Well we know the top is the same as the bottom and both are 4 square ft. Then, if we look at it from the side, we know two sides are (1/2 x 1) so that's another square foot (9 total now). Finally, you need to look at it from the last two sides. And those two sides would be: \[2\times((1\times {1 \over 2}) + (1\times{1 \over 3}) + (1\times{1 \over 17}) + (1\times{11 \over 102}))\] which, after solving, gets 11 square ft. or answer E.
but the last two sides are overlapping...so wouldn't they equal 1 each?
oh...nevermind...I get it. thank you!
If you want to see their solution, which doesn't explain how to get the heights very well is here. http://www.artofproblemsolving.com/Wiki/index.php/2009_AMC_8_Problems/Problem_25
8 + 1 + 2/3 + 3/17 + 33/102 + 5/6 A - D + A-B + B-C = 2A - D - C = 1 - 11/102 - 1/17 = 5/6 E is the answer
AH! I totally get it now! THANKS A TON!!!! :D
No problem. Wish you luck
thanks!
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