Question

Hey guys so im stuck on a problem!!
it is
x^2-5x+1=0

so far i got
x^2-5x+25/4=-1(25/4)

what i want to know is how to Write the left side as the
square of a binomial. Hey guys so im stuck on a problem!!
it is
x^2-5x+1=0

so far i got
x^2-5x+25/4=-1(25/4)

what i want to know is how to Write the left side as the
square of a binomial. @Mathematics

Answer 1

\[(x-5/2)^2=x^2-5x+25/4\]

Answer 2

btw the right side is -1 +25/4 makes a HUGE DIFFERENCE

Answer 3

correct - I was answering your "left-side" question.

Answer 4

oh okay thanks!

Answer 5

:-) yw

Answer 6

MEtal for you (^.^)

Answer 7

What next?

Answer 8

hummm? i got the rest

Answer 9

(x-5/2)^2=21/4
Good, keep up the good work

Answer 10

thanks