Question

Find the distance from (2, 8, 5) to the plane x − 2y − 2z = 1. Ans: 25/3

Answer 1

I put this in parametric form, but I'm not sure how to find the intersection. [x, y, z] = [1, -2, -2]t + [2, 8, 5]

Answer 2

d=|1(2)-2(8)-2(5)-1|/sqrt(1^2+(-2)^2+(-2)^2)

Answer 3

use the distance from a plane formula

Answer 4

d= |A(x1)+ B(y1) + C(z1) + d|/sqrt(A^2 + B^2 +C^2)

Answer 5

ah, I got it. thank you so much!