Question

Solve the equation: x^4+x^2-6=0

Answer 1

How are we supposed to solve it? like for ex: (2x +1) (x+5) btw thats not the answer.

Answer 2

Try using the Quadratic Formula?

Answer 3

(x^2-2)(x^2+3)=0
can you finish it?

Answer 4

How did you get that?

Answer 5

subsitution method:

x^4+x^2-6=0

lets say x^2=a, then

a^2+a-6=0

x1=-3
x2= 2

x^2=-3
and x^2=2
x= +/- sqrt2

Answer 6

x1=-3 x2= 2those are not x1 and x2. They are a1 and a2
my bad

Answer 7

by factoring

x^2*x^2=x^4
x^2*3=3x^2
x^2*-2=-2x^2
-2*3=-6

X^4+3x^3-2x^2-6

simplifies to x^4+x^2-6

Answer 8

\[x^4+x^2-6 = 0\]\[x^4 +3x^2-2x^2 - 6 = 0\]\[x^2(x^2+3)-2(x^2+3) = 0 \]\[(x^2+3)(x^2-2) =0 \]

Answer 9

Factor by Grouping Method

Answer 10

3x^2-2x^2 wouldn't that be just x^2?????

Answer 11

Yes, I substituted x^2 for 3x^2 - 2x^2

Makes it easier to factor

Answer 12

Let me guess...

You still don't get it..

Answer 13

Ok, thx