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so what is the vertex of f(x)=3x^2-12x+21
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use: -b/2a, to find the x coordinate of the vertex, then once you find it, you can plug that value back into the orginal function and get the y coordiante of the vertex
so the vertex would be (3,21)
vertex would be(2,9)
Good try i guess
Use calculus; things simplify tenfold:\[f'(x)=6x-12=0\implies x=2\]\[f(2)=3(2)^2-12(2)+21=9\]\[(2,9)\]and Lagrange is correct.
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