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find the fixed points or points of the function if any g(x)=x^2-4x+1
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what do you mean fixed points?
i think he meant roots
no it says fixed points of a function
what is fixed points of a functin..?
A fixed point is a point that's mapped to itself.
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But I don't know if they have root or not that is why I am asking
so how do you find that?
we cant find its roots so we use b^2-4ac= delta
then x should be equal y \[x=x^2-4x+1\] \[x^2-5x+1=0\] I hope you can solve this quadratic equation yourself and answer will be \[(\frac{5-\sqrt{21}}{2};\frac{5-\sqrt{21}}{2})\] \[(\frac{5+\sqrt{21}}{2};\frac{5+\sqrt{21}}{2})\]
you complete me guy
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I will try thanks
I had help with this earlier but I had a hard time following.
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