Question

solve
3+sqrt z-11=sqrt z+4

Answer 1

post the question clearly using the equation button below
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Answer 2

alright. square both sides and post what you get.

Answer 3

idk how to use equation editor lol i tried

Answer 4

i dont know how to square both sides... i dont even know what that means

Answer 5

z-22 and z+8 ??

Answer 6

no no.
square simply means taking a number and multiplying it by itself.
for example,
4 multiplied by itself gives 16. that is,
4 x 4 = 16
therefore 16 is the square of 4.
conversely, 4 is the square root of 16 since 4 is the root or the starting point.

Answer 7

OHHH

Answer 8

so its-120 and 16

Answer 9

i need to get my calculator out lol

Answer 10

so what fdo I do with the 3 ?

Answer 11

so when you have
\[(3\sqrt{z-11})^2 = 3^2 \times (\sqrt{z-11})^2\]

Answer 12

now, remember that
\[4 = \sqrt {16}\]
\[(\sqrt{16})^2 = 4^2 = 16\]

Answer 13

\[3 + \sqrt{z+11} = \sqrt{z+4}\]
is this question?

Answer 14

yes sheg

Answer 15

ok

Answer 16

wait, is 3 added or multiplied?

Answer 17

oh pellet its added my bad

Answer 18

i didnt realize i typed it wrong until just now Im so sorry

Answer 19

i like how they bleep out my pellet with pellet fluttering retarded

Answer 20

lmfao ha ha

Answer 21

\[9 + 6\sqrt{z-11} + z-11 = z+4\]
\[6\sqrt{z-11} = 6\]
\[\sqrt{z-11} = 1\]
\[{z-11} = 1\]
\[{z} = 12\]

Answer 22

well where did the 3 go?

Answer 23

so u have z=12

Answer 24

awesome i only have like 5 more ?'s

Answer 25

(a+b)^2= a^2+(2*a*b)+B^2 this is how to solve a polynomial
equation of a second degree so in your equation is a=3 and b=root squirt (z-11)
you apply the formula and you will know where did the 3 go