Question

solve for t: 0=t^2-2t-1

Answer 1

Factor it.

Answer 2

t1,2=(2+/- sqrt8)/2 = 1+/-sqrt2

Answer 3

what do you mean by t1,2?

Answer 4

those two roots

Answer 5

those two zeros of this function

Answer 6

ok ?

Answer 7

so do I put that there are no points?

Answer 8

check those hence (t -(1+sqrt2))(t-(1-sqrt2))

Answer 9

and you need getting this equation like result

Answer 10

t^2-2t-1=(t-1)^2-2

now solve (t-1)^2=2

Answer 11

that is how I was doing it.

Answer 12

yes but if you make those calcules what i have wrote you will get the same sure

Answer 13

so there are many ways to do this problem????

Answer 14

ok

Answer 15

yes i have doit those calcules by discriminant

Answer 16

ok ?

Answer 17

am I back to being not sure about myself . Yes

Answer 18

I have not done discriminants yet

Answer 19

so if you are not sure than check it by calcules

Answer 20

ok

Answer 21

ok but you know how can being solved one quadratic equation by used discriminant ?

Answer 22

somewhat yes

Answer 23

so we know that D=b2-4ac and t1,2 =(-b+/- sqrt(D))/2a
right ?

Answer 24

yes

Answer 25

so now check it my firstly calcules and will can seeing the results

Answer 26

my calc won't let me do it?

Answer 27

D=b2-4ac = 4 -4*1*(-1)=4+4=8

t1,2=(-b+/- sqrtD)/2a=(2+/-sqrt8)2=(2+/-2sqrt2)/2=2(1+/-sqrt2)/2=
=1+/-sqrt2

Answer 28

ok ?

Answer 29

yep

Answer 30

so than give medal

Answer 31

and good luck bye

Answer 32

Thanks

Answer 33

yw