Question

y varies jointly with p and q. When p = 10 and q = 2, y = 60. Find y when p = 5 and q = 5







y = 300








y = 250








y = 100








y = 75

Answer 1

75

Answer 2

I'd say, y = 75.... I am not completely sure though. Nevertheless...!

Answer 3

y= 3pq

Answer 4

yeah according to me also 75

Answer 5

(10*2)*3=60
similarily,
(5*5)*3=75

Answer 6

\(y\) varies jointly with \(p\) and \(q\) mean \(y=kpq\), where k is some constant needed to be found. We have \(60=k(10)(2) \implies k=3\). That means that our equation would be \(y=3pq\). So at \(p=q=5\), \(y=3(5)(5)=75\).