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exponential equation 8^(x^2+(5x/3))=16^(x+(1/2) i meant 8 raise to power x square+ 5x/3=16 raise to power x+ 1/2.
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same gimmick as before write \[8=2^3\] \[16=2^4\] multiply the exponents by 2 and 4 respectively and then set them equal and solve
*3 and 4 respectively
\[8^{x^2+\frac{5x}{3}}=16^{x+\frac{1}{2}}\] \[2^{3(x^2+\frac{5x}{3})}=2^{4(x+\frac{1}{2})}\] \[3(x^2+\frac{5x}{3})=4(x+\frac{1}{2})\] I hope you can solve now urself?
yeah thanks man
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