find the value of sin, cosine, tangent using these double angle identities. please check if my equation is correct. cos 2A = 1-2sin^2A then it will be
\[sinA = \sqrt{(1-\cos2A)/2}\]
and\[\cos2A = 2\cos ^{2}A-1\] will be\[cosA = \sqrt{(\cos2A+1)/2}\]
correct so far
and \[tanA = sinA/cosA\] will be \[\sqrt{(1-\cos2A)/(\cos2A-1} = tanA\]
you got the last one wrong
denominator should have a plus sign instead of a minus sign
you seem to be pretty good at them already - just follow your instinct and use logical steps
and do you have some tips to give so that will help me master these equations?
you don't need to remember all the equations. as long as you know the basic relationships, you should be able to derive all the rest.
Actually, my teacher made the derivation I am just checking if I copied the correct one. :) But i'll derive it myself later so that I can practice. Thanks!
yw
Join our real-time social learning platform and learn together with your friends!