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I need help solving by the elimination method 3x+4y=5 6x+8y=10
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multiply the first equation by -2 and add it to the second, what do you get?
-6x+-8y=-10
?
yes, now add it to the other equation, what do you get?
0
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So there is no solution
infinitely many solutions
both sides please
So the answer would be there are infinitely many solutions?
Yes, exactly ALL REALS This makes for a bad example of the elimination method, but it is the correct answer in this case.
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thank you
because 0=0 is always true
you should write down the solution let x=t be any real number then \[y=\frac{5-3t}{4}\]
More specifically, yes; but they don't usually ask that of you in basic algebra, which I'm guessing this is. Hence I neglected it.
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