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Mathematics 18 Online
OpenStudy (precal):

cosθ−sinθ=1

OpenStudy (anonymous):

theta =0

OpenStudy (anonymous):

no it's not

OpenStudy (anonymous):

more generally it's solved at -pi/2 * 2pi k and 2pi * k for all k

OpenStudy (anonymous):

i mean -pi/2 + 2pi k and 2pi k

OpenStudy (anonymous):

where do you get sin(t) = cos(t)? the original equation was sin(t)-cos(t)=1

OpenStudy (anonymous):

i mean cos(t)-sin(t)=1

OpenStudy (anonymous):

right i misread the question

OpenStudy (precal):

I double checked. I was told they were identities but I just had the person who told me that they were identites check and yes I stand corrected. They are equations.

OpenStudy (precal):

Sorry, I did not mean to mislead.

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