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cosθ−sinθ=1
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theta =0
no it's not
more generally it's solved at -pi/2 * 2pi k and 2pi * k for all k
i mean -pi/2 + 2pi k and 2pi k
where do you get sin(t) = cos(t)? the original equation was sin(t)-cos(t)=1
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i mean cos(t)-sin(t)=1
right i misread the question
I double checked. I was told they were identities but I just had the person who told me that they were identites check and yes I stand corrected. They are equations.
Sorry, I did not mean to mislead.
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