What is the equation of the line passing through (1, 7) and parallel to the line y = –x + 5 in standard form?
Answer

x – y = 8

x – y = –8

x + y = 8

x + y = –8

Question

What is the equation of the line passing through (1, 7) and parallel to the line y = –x + 5 in standard form?
Answer
		
x – y = 8
		
x – y = –8
		
x + y = 8
		
x + y = –8

anonymous · Answer

the third equation

anonymous · Answer

parallel means they should have the same slope
$$y-7=-(x-1)$$$$y-7=-x+1$$$$y=-x+8$$$$x+y=8$$

anonymous · Answer

sarah how did you get -x? if u dont mind cud u explain it please

anonymous · Answer

Parallel lines have the same slope so both lines should have a slope of -1.  We know the given line has a slope of -1 because it is written in slope-intercept form: y=mx+b===>y = –x + 5 . By the definition of slope (rise/run), and starting at the given point our line is supposed to pass through (i.e., (1,7)):$$m=\Delta y/\Delta x=\frac{y-7}{x-1}=-1$$Thus,$$y-7=-(x-1)$$etc....