What is the equation of the line passing through (8, –6) and perpendicular to the line y = x – 2 in slope-intercept form?
Answer

y = –x – 2

y = x + 2

y = –x + 2

y = x – 2

Question

What is the equation of the line passing through (8, –6) and perpendicular to the line y = x – 2 in slope-intercept form?
Answer
		
y = –x – 2
		
y = x + 2
		
y = –x + 2
		
y = x – 2

akshay_budhkar · Answer

y=-x+2.. Do u want me to explain?

anonymous · Answer

yes please

akshay_budhkar · Answer

ok we know the gerenal equation of a line is y=mx+c where m is the slope.

Now if two lines are perpendicular the we have the product of their slopes to be -1.

therefore in this case the slope of the line perpendicular to the original one is -1

akshay_budhkar · Answer

so the equation of the line is y=-x+c
now it is given that it passes through ( 8,-6)
so we subsititute the values to get the value of c

akshay_budhkar · Answer

um am i clear?