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What is the equation of the line passing through (8, –6) and perpendicular to the line y = x – 2 in slope-intercept form? Answer y = –x – 2 y = x + 2 y = –x + 2 y = x – 2
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y=-x+2.. Do u want me to explain?
yes please
ok we know the gerenal equation of a line is y=mx+c where m is the slope. Now if two lines are perpendicular the we have the product of their slopes to be -1. therefore in this case the slope of the line perpendicular to the original one is -1
so the equation of the line is y=-x+c now it is given that it passes through ( 8,-6) so we subsititute the values to get the value of c
um am i clear?
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